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9a^2+3a-30=0
a = 9; b = 3; c = -30;
Δ = b2-4ac
Δ = 32-4·9·(-30)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-33}{2*9}=\frac{-36}{18} =-2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+33}{2*9}=\frac{30}{18} =1+2/3 $
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